The call method in JavaScript: Difference between revisions

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passed in as the first argument. The second argument is the color argument, the only one for either
passed in as the first argument. The second argument is the color argument, the only one for either
class.
class.

[[Category:Programming language]]

Revision as of 23:35, 16 January 2007

The call() method is the method most similar to the classic object-masquerading method. Its first argument is the object to be used for this. All other arguments are passed directly to the function itself. For example:

function sayColor(sPrefix, sSuffix) {
alert(sPrefix + this.color + sSuffix);
};
var obj = new Object();
obj.color = “red”;
//outputs “The color is red, a very nice color indeed. “
sayColor.call(obj, “The color is “, “, a very nice color indeed. “);

In this example, the function sayColor() is defined outside of an object, and it references the this keyword even though it is not attached to any object. The object obj is given a color property equal to “red”. When call() is, well, called, the first argument is obj, which indicates that the this keyword in sayColor() should be assigned the value of obj. You can edit JavaScript code by JavaScript editor. The second and third arguments are strings. They are matched up with the prefix and suffix arguments of sayColor(), resulting in the message “The color is red, a very nice color indeed.” being displayed. To use this with the object masquerading method of inheritance, just replace the three lines that assign, call, and delete the new method:

function ClassB(sColor, sName) {
//this.newMethod = ClassA;
//this.newMethod(sColor);
//delete this.newMethod;
ClassA.call(this, sColor);
this.name = sName;
this.sayName = function () {
alert(this.name);
};
}

Here, you want the this keyword in ClassA to be equal to the newly created ClassB object, so this is passed in as the first argument. The second argument is the color argument, the only one for either class.